n2 (1 + 1
Page 1. TS1. 2013/2014. Correction de l'exercice n?42a)c) p 119 et d'une limite?. ? Notons un = 2n3 ? n n2 + n + 1 . On a un = n2 (2n ? 1 n. ) n2 (1 + 1 n.
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